(4x^2-x+5)=0

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Solution for (4x^2-x+5)=0 equation:


Simplifying
(4x2 + -1x + 5) = 0

Reorder the terms:
(5 + -1x + 4x2) = 0

Remove parenthesis around (5 + -1x + 4x2)
5 + -1x + 4x2 = 0

Solving
5 + -1x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
1.25 + -0.25x + x2 = 0

Move the constant term to the right:

Add '-1.25' to each side of the equation.
1.25 + -0.25x + -1.25 + x2 = 0 + -1.25

Reorder the terms:
1.25 + -1.25 + -0.25x + x2 = 0 + -1.25

Combine like terms: 1.25 + -1.25 = 0.00
0.00 + -0.25x + x2 = 0 + -1.25
-0.25x + x2 = 0 + -1.25

Combine like terms: 0 + -1.25 = -1.25
-0.25x + x2 = -1.25

The x term is -0.25x.  Take half its coefficient (-0.125).
Square it (0.015625) and add it to both sides.

Add '0.015625' to each side of the equation.
-0.25x + 0.015625 + x2 = -1.25 + 0.015625

Reorder the terms:
0.015625 + -0.25x + x2 = -1.25 + 0.015625

Combine like terms: -1.25 + 0.015625 = -1.234375
0.015625 + -0.25x + x2 = -1.234375

Factor a perfect square on the left side:
(x + -0.125)(x + -0.125) = -1.234375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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